35n^2-300n+160=0

Solution for 35n^2-300n+160=0 equation:

35n^2-300n+160=0

a = 35; b = -300; c = +160;
Δ = b2-4ac
Δ = -3002-4·35·160
Δ = 67600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{67600}=260$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-300)-260}{2*35}=\frac{40}{70}
=4/7
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-300)+260}{2*35}=\frac{560}{70}
=8
$